2^(3x-x^2)=2^2

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Solution for 2^(3x-x^2)=2^2 equation: 



2^(3x-x^2)=2^2

We move all terms to the left:

2^(3x-x^2)-(2^2)=0

We add all the numbers together, and all the variables

2^(3x-x^2)-4=0

We move all terms containing x to the left, all other terms to the right

2^(3x-x^2)=4

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